Deepa Rao6 days agoHow I finally understood the chain ruleš„ 0 engagedIf y=f(g(x))y=f(g(x))y=f(g(x)) then dydx=fā²(g(x))āgā²(x)\frac{dy}{dx}=f'(g(x))\,g'(x)dxdyā=fā²(g(x))gā²(x) ā derivatives multiply along the chain.Think of it as units cancelling: dyduā dudx\frac{dy}{du}\cdot\frac{du}{dx}dudyāā dxduā.0š0ā¤ļø0š¬ 0SaveShareComments (0)Log in to add a comment.
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